转自https://blog.csdn.net/Thomas0713/article/details/83028414
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| x = [{'a': 3}, {'b': 1}, {'c': 5}]
list_a = [] # 初始化一个列表
for i in x: # 遍历列表中的字段
for j in i.keys(): # 取出key
list_a += {j: i[j]}.items() # 把字典转换成元组
aa = sorted(list_a, key=lambda value: value[1]) # 对列表中的元组排序
list_b = [{i[0]: i[1]} for i in aa] # 把元组再转换成字典
print(list_b)
#######################################
[{'b': 1}, {'a': 3}, {'c': 5}]
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等同于
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| x = [{'a': 3}, {'b': 1}, {'c': 5}]
list_a = sorted({j: i[j] for i in x for j in i.keys()}.items(), key=lambda value: value[1])
list_b = [{i[0]: i[1]} for i in list_a]
print(list_b)
#######################################
[{'b': 1}, {'a': 3}, {'c': 5}]
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以下转自https://www.runoob.com/python3/python3-func-sorted.html
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| array = [{"age":20,"name":"a"},{"age":25,"name":"b"},{"age":10,"name":"c"}]
array = sorted(array,key=lambda x:x["age"])
print(array)
################################
[{'age': 10, 'name': 'c'}, {'age': 20, 'name': 'a'}, {'age': 25, 'name': 'b'}]
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| #先按照成绩降序排序，相同成绩的按照名字升序排序：
d1 = [{'name':'alice', 'score':38}, {'name':'bob', 'score':18}, {'name':'darl', 'score':28}, {'name':'christ', 'score':28}]
l = sorted(d1, key=lambda x:(-x['score'], x['name']))
print(l)
############################################
[{'name': 'alice', 'score': 38}, {'name': 'christ', 'score': 28}, {'name': 'darl', 'score': 28}, {'name': 'bob', 'score': 18}]
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